autumnsteeg
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  • 03-10-2016
  • Mathematics
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How do I solve for 8/(y+3) = 4/3y

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MahmoudMlouk MahmoudMlouk
  • 03-10-2016
To solve this equation we can easily apply cross multiplication acknowledging that y is different from 0 and -3 to ensure that the denominator is not Zero
This gives :
8 × 3y = 4 × ( y + 3)
24y = 4y + 12
24y - 4y = 12
20y = 12
y = 12/20
Then y = 3/5 or in decimal form y = 0.6
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