-2(3y 1)=-4y 10 how do i solve this equation?

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01-10-2016
Mathematics

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-2(3y 1)=-4y 10 how do i solve this equation?

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(10y^3+20y^2+55y)/5y

AmanRanaTG AmanRanaTG · Answer 1 · 2016-10-01T19:23:20+02:00

AmanRanaTG AmanRanaTG

01-10-2016

= -6y +-2 = -4y +10 (i exxpanded the first bracket)
= -2y +-2= +10(i moved the y to one side)
= -2y = 8 ( I added two to both sides)
= y = -4 (Just divide 8 by -2)

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