ritasopindutch ritasopindutch
  • 04-08-2020
  • Mathematics
contestada

HELP!!!
The solutions to (x + 3)^2- 4=0 are x = -1 and x = -5

True or false

Respuesta :

19allenethm
19allenethm 19allenethm
  • 04-08-2020

Answer:

False

Step-by-step explanation:

We can simplify this equation and then solve for x.

[tex](x+3)^3-4=0\\\\x^2+6x+9-4=0\\\\x^2+6x+5=0\\\\(x+2)(x+3)=0\\\\x=-3\\x=-2[/tex]

As you can see, the solutions are not x=-1 and x=-5.

Therefore, the answer is false.

Answer Link
jimrgrant1 jimrgrant1
  • 04-08-2020

Answer:

True

Step-by-step explanation:

Given

(x + 3)² - 4 = 0 ( add 4 to both sides )

(x + 3)² = 4 ( take the square root of both sides )

x + 3 = ± [tex]\sqrt{4}[/tex] = ± 2 ( subtract 3 from both sides )

x = - 3 ± 2

Thus

x = - 3 - 2 = - 5

x = - 3 + 2 = - 1

Answer Link

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