kmus3ceterose
kmus3ceterose kmus3ceterose
  • 01-07-2016
  • Mathematics
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what is the solution to –4(8 – 3x) ≥ 6x – 8? x ≥ –4/3 x ≤ –4/3 x ≥ 4 x ≤ 4

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Cata9 Cata9
  • 14-04-2017
The solution to –4(8 – 3x) ≥ 6x – 8 is x ≥ 4. –4(8 – 3x) ≥ 6x – 8. Multiply the factors on the left side: (-4)*8 - (-4)*3x ≥ 6x – 8. -32 + 12x ≥ 6x – 8. Add 32 on both sides of the equation: 32 - 32 + 12x ≥ 6x – 8 + 32. 12x ≥ 6x + 24. Subtract 6x from both sides of the equation: 12x - 6x ≥ 6x + 24 - 6x. 6x ≥ 24. x ≥ 24/6. x ≥ 4.
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barredharpy1010 barredharpy1010
  • 14-01-2021

Answer:X>4

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