ajelirio ajelirio
  • 02-02-2020
  • Mathematics
contestada

Take a factor out of the square root: 48x^2 , where x≤0

Respuesta :

bayosanuade
bayosanuade bayosanuade
  • 02-02-2020

Answer: [tex]4/x/\sqrt{3}[/tex]

Step-by-step explanation:

[tex]\sqrt{48x^{2} }[/tex]

this could also be written as :

[tex]\sqrt{48}[/tex] x [tex]\sqrt{x^{2}}[/tex]

[tex]\sqrt{x^{2}}[/tex] = ±[tex]x[/tex] , so we have

[tex]\sqrt{48}/x/[/tex]

[tex]\sqrt{48}[/tex] could be written as: [tex]\sqrt{16}[/tex] x [tex]\sqrt{3}[/tex]

which will result into [tex]4\sqrt{3}[/tex]

combining all together , we have

[tex]4/x/\sqrt{3}[/tex]

Therefore , one of the factor of [tex]\sqrt{48x^{2} }[/tex] is [tex]4/x/\sqrt{3}[/tex]

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