Bleh51 Bleh51
  • 02-02-2020
  • Mathematics
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How do I prove that 5^31-5^29 is divisible by 100
in the form of ___*100?

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LammettHash
LammettHash LammettHash
  • 02-02-2020

You can pull a common factor from both terms:

[tex]5^{31}-5^{29}=5^{29+2}-5^{29}=5^{29}(5^2-1)=24\cdot5^{29}[/tex]

Next, pull a factor of 4 from 24, and 25 from the power of 5; since 100 = 25*4, we have

[tex]5^{31}-5^{29}=\underbrace{5^{27}\cdot6}\cdot100[/tex]

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