kausarjehan1 kausarjehan1
  • 02-03-2019
  • Mathematics
contestada

If x=1,y=3,z=4 evaluate x^2+y^2+z^2-3yz^2

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Аноним Аноним
  • 02-03-2019

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➷ Just substitute the values in:

(1)^2 + (3)^2 + (4)^2 - 3(3)(4)^2

Simplify:

(1 + 9 + 16) - 144

Simplify further to get the answer:

answer = -118

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